Practicing Success
If $A=\left[\begin{array}{ccc}1 & -2 & 3 \\ -4 & 2 & 4\end{array}\right]$ and $B=\left[\begin{array}{cc}1 & -2 \\ 3 & -4 \\ 2 & 4\end{array}\right]$ then product AB is : |
Not possible $\left[\begin{array}{ccc}1 & -6 & 6 \\ 8 & -8 & 16\end{array}\right]$ $\left[\begin{array}{c}9 \\ 19 \\ 15\end{array}\right]$ $\left[\begin{array}{cc}1 & 18 \\ 10 & 16\end{array}\right]$ |
$\left[\begin{array}{cc}1 & 18 \\ 10 & 16\end{array}\right]$ |
$A=\left[\begin{array}{ccc}1 & -2 & 3 \\ -4 & 2 & 4\end{array}\right]$ $B=\left[\begin{array}{cc}1 & -2 \\ 3 & -4 \\ 2 & 4\end{array}\right]$ $A B=\left[\begin{array}{ccc}1 & -2 & 3 \\ -4 & 2 & 4\end{array}\right]\left[\begin{array}{cc}1 & -2 \\ 3 & -4 \\ 2 & 4\end{array}\right]$ $=\left[\begin{array}{cc}1-6+6 & -2+8+12 \\ -4+6+8 & 8-8+16\end{array}\right]$ $=\left[\begin{array}{cc}1 & 18 \\ 10 & 16\end{array}\right]$ |