Let $\vec{a} = 2\hat{i}+3\hat{j}-4\hat{k}$ and $\vec{b} = 3\hat{i}-5\hat{j}+6\hat{k}$. Let $\vec{c}$ be a vector such that $\vec{c}×\vec{a}=\vec{b}×\vec{c}$ and $\vec{c}.(2\vec{a}-3\vec{b})=238\sqrt{2}$ then $|\vec{c}|^2$ is equal to:
Answer & explanation
Correct answer: option 3
A detailed explanation for this question is coming soon.