Practicing Success
Practicing Success
CUET Preparation Today
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a b c d |
b |
$\frac{1}{\lambda} = Rz^2(\frac{1}{1^2} - \frac{1}{2^2})$ $\Rightarrow \lambda = \frac{4}{3Rz^2}$ $\Rightarrow \lambda_1 = \frac{4}{3R}$ $\Rightarrow \lambda_2 = \frac{4}{3R}$ $\Rightarrow \lambda_3 = \frac{4}{12R}$ $\Rightarrow \lambda_4 = \frac{4}{27R}$ $\Rightarrow \lambda_1 = \lambda_2 = 4\lambda_3 = 9\lambda_4$ |
