Practicing Success

Target Exam

CUET

Subject

Physics

Chapter

Electromagnetic Waves

Question:

In a plane electromagnetic wave electric field varies with time having an amplitude 1 Vm−1 . The frequency of wave is 0.5 × 1015 Hz. The wave is propagation along X-axis. What is the average energy density of magnetic field?

Options:

1.1 × 10−12J m−3

2.2 × 10−12J m−3

3.3 × 10−12J m−3

4.4 × 10−12J m−3

Correct Answer:

2.2 × 10−12J m−3

Explanation:

In an electromagnetic wave, the average energy density of magnetic field $\mu_B$ = average energy density of electric filed $v_E =\frac{1}{4}ε_0E^2_0$

$=\frac{1}{4}×(8.85×10^{-12})×1^2$

$=2.21 × 10^{-12} Jm^{-3}$