For x ∈ [-1,1] , if 4 sin^-1x + cos^-1x = π then x is equal to

The correct answer is Option (2) → \(\displaystyle\frac{1}{2}\)

For \(x \in [-1, 1]\), the identity \(\sin^{-1}x + \cos^{-1}x = \frac{\pi}{2}\) gives

    \( \displaystyle \cos^{-1}x = \frac{\pi}{2} - \sin^{-1}x \)

Substituting in the equation:

    \( \displaystyle 4\sin^{-1}x + \frac{\pi}{2} - \sin^{-1}x = \pi \)

    \( \displaystyle 3\sin^{-1}x = \frac{\pi}{2} \)

    \( \displaystyle \sin^{-1}x = \frac{\pi}{6} \)

    \( \displaystyle x = \sin\frac{\pi}{6} = \frac{1}{2} \)

Note: This topic was not in the CUET 2026 syllabus.