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A series AC circuit has a resistance 8 Ω and a reactance of 6 Ω. The impedance of the circuit is : |
14 Ω 10 Ω $\frac{35}{6} Ω$ 7 Ω |
10 Ω |
The correct answer is Option (2) → 10 Ω The impedance (Z) of an AC circuit with resistance (R) and reactance (X) is - $Z=\sqrt{R^2+X^2}$ Given, $X=6Ω$ and $R=8Ω$ $Z=\sqrt{8^2+6^2}=10Ω$ |
