Is cos x = $\frac{5}{13}$, then what is the value of tanx + cot x ?
Answer & explanation
Correct answer: option 2
We are given that ,
cos x = \(\frac{5}{13}\)
{ we know, cos A = \(\frac{B}{H}\) }
By using pythagoras theorem ,
P² + B² = H²
P² + 5² = 13²
P = 12
Now,
tanx + cotx
= \(\frac{12}{5}\) + \(\frac{5}{12}\)
= \(\frac{169}{60}\)