Is cos x = $\frac{5}{13}$, then what is the value of tanx + cot x ?

$\frac{169}{109}$ $\frac{169}{60}$ $\frac{109}{169}$ $\frac{60}{169}$

$\frac{169}{60}$

We are given that , cos x = \(\frac{5}{13}\) { we know, cos A = \(\frac{B}{H}\) } By using pythagoras theorem , P² + B² = H² P² + 5² = 13² P = 12 Now, tanx + cotx = \(\frac{12}{5}\) + \(\frac{5}{12}\) = \(\frac{169}{60}\)