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If tanθ - cot θ = 12 , find the value of tan3θ - cot3θ . |
1764 1556 1784 1760 |
1764 |
Formula I → [ cotθ = \(\frac{1}{tanθ}\)] Formula II → [If x - \(\frac{1}{x}\) = n and x3 - \(\frac{1}{x^3}\) = n3 + 3n] tanθ - \(\frac{1}{tanθ}\) = 12 ⇒ tan3θ - \(\frac{1}{tan^3θ}\) = (12)3 + 3 × 12 ⇒ tan3θ - cot3θ = 1728 + 36 = 1764 |
