If x - y - z = 0, then the value of (x^2+y^2+z^2)÷(y^2+xz) is :

If x - y - z = 0,

then the value of $(x^2+y^2+z^2)÷(y^2+xz)$= ?

As there are two equation and three variables we can put z = 0 and x = 1 and y = -1. These values will satisfy the given equation.

then the value of $(1^2+(-1)^2+0)÷((-1)^2+0)$= 2