If x - y - z = 0, then the value of $(x^2+y^2+z^2)÷(y^2+xz)$ is :

-2 2 1 -1

2

If x - y - z = 0, then the value of $(x^2+y^2+z^2)÷(y^2+xz)$= ? As there are two equation and three variables we can put z = 0 and x = 1 and y = -1. These values will satisfy the given equation. then the value of $(1^2+(-1)^2+0)÷((-1)^2+0)$= 2