If a + b + c = 0, then ((2a^2)/3bc+(2b^2)/3ca+(2c^2)/3ab) is equal to…

If $ a + b + c = 0$,

then $(\frac{2a^2}{3bc}+\frac{2b^2}{3ca}+\frac{2c^2}{3ab})$ is equal to =?

If a + b + c = 0

Then, a³ + b³ + c³ = 3abc

$(\frac{2a^2}{3bc}+\frac{2b^2}{3ca}+\frac{2c^2}{3ab})$ = \(\frac{2a^3 + 2b^3 + 2c^3}{3abc}\)

= 2×\(\frac{3abc}{3abc}\) = 2