The three medians AX, BY and CZ of ΔABC intersect at point L. If the area of ABC is 30 cm2, then the area of the quadrilateral BXLZ is:

12 cm2 16 cm2 10 cm2 14 cm2

10 cm2

We have, Area of ΔABC = 30 cm2 According to the concept, When three medians of Δ ABC intersect at point L Area of ΔBLX = \(\frac{1}{6}\) × ΔABC = Area of ΔBLX = \(\frac{1}{6}\) × 30 = 5 cm2 Area of BXLZ = 2 × ΔBLX = Area of BXLZ = 2 × 5 = 10 cm2