The three medians AX, BY and CZ of ΔABC intersect at point L. If the area of ABC is 30 cm², then the area of the quadrilateral BXLZ is:

10 cm²

We have,

Area of ΔABC = 30 cm²

According to the concept,

When three medians of Δ ABC intersect at point L

Area of ΔBLX = \(\frac{1}{6}\) × ΔABC

= Area of ΔBLX = \(\frac{1}{6}\) × 30 = 5 cm²

Area of BXLZ = 2 × ΔBLX

= Area of BXLZ = 2 × 5 = 10 cm²