The three medians AX, BY and CZ of ΔABC intersect at point L. If the area of ABC is 30 cm2, then the area of the quadrilateral BXLZ is:
Answer & explanation
Correct answer: option 3
We have,
Area of ΔABC = 30 cm2
According to the concept,
When three medians of Δ ABC intersect at point L
Area of ΔBLX = \(\frac{1}{6}\) × ΔABC
= Area of ΔBLX = \(\frac{1}{6}\) × 30 = 5 cm2
Area of BXLZ = 2 × ΔBLX
= Area of BXLZ = 2 × 5 = 10 cm2