Practicing Success

Target Exam

CUET

Subject

-- Mathematics - Section A

Chapter

Indefinite Integration

Question:

Find the integral of the function y = x-1 with respect to x

Options:

\[\frac{ { x }^{ 2 } }{2} + x + c\]

\[\frac{ { -x }^{ 2 } }{2} - x + c\]

\[\frac{ { x }^{ 2 } }{2} - x + c\]

\[\frac{ {- x }^{ 2 } }{2}+ x + c\]

Correct Answer:

\[\frac{ { x }^{ 2 } }{2} - x + c\]

Explanation:

\[\int x dx = \frac{ { x }^{ 2 } }{2}+c\]