If tan $θ = \frac{4}{3}$, then the value of $\frac{9sinθ +12 cosθ}{27cosθ-20sinθ}$ will be equal to :

72 36 18 100

72

tan θ = \(\frac{4}{3}\) { tan θ = \(\frac{P}{B}\) } By using pythagoras theorem , P² + B² = H² 4² + 3² = H² H = 5 Now, \(\frac{9sinθ + 12cosθ}{27cosθ - 20sinθ}\) = \(\frac{9 × 4 + 12 ×3}{27 ×3 - 20 ×4}\) = \(\frac{72}{1}\) = 72