If $(p^2 +\frac{1}{p^2}=14)$, then find the value of $(p^3 +\frac{1}{p^3})$.
Answer & explanation
Correct answer: option 4
If, x2 + \(\frac{1}{x^2}\) = b
then x + \(\frac{1}{x}\) = \(\sqrt {b + 2}\)
If x + \(\frac{1}{x}\) = n
then, $x^3 +\frac{1}{x^3}$ = n3 - 3 × n
If $(p^2 +\frac{1}{p^2}=14)$
Then find the value of $(p^3 +\frac{1}{p^3})$
$(p +\frac{1}{p})$ = \(\sqrt {14 + 2}\) = 4
$(p^3 +\frac{1}{p^3})$ = 43 - 3 × 4 = 52