If $(p^2 +\frac{1}{p^2}=14)$, then find the value of $(p^3 +\frac{1}{p^3})$.

56 60 48 52

52

If, x2 + \(\frac{1}{x^2}\) = b then x + \(\frac{1}{x}\) = \(\sqrt {b + 2}\) If x + \(\frac{1}{x}\)  = n then, $x^3 +\frac{1}{x^3}$ = n3 - 3 × n If $(p^2 +\frac{1}{p^2}=14)$ Then find the value of $(p^3 +\frac{1}{p^3})$ $(p +\frac{1}{p})$ = \(\sqrt {14 + 2}\) = 4 $(p^3 +\frac{1}{p^3})$ = 43 - 3 × 4 = 52