CUET Preparation Today
The value of $\tan ^2\left(\sec ^{-1} 2\right)$ is : |
5 3 4 6 |
3 |
The correct answer is option 2: 3 $y=\tan ^2\left(\sec ^{-1} 2\right)$ we know that $\sec ^{-1} 2=\cos ^{-1} \frac{1}{2}=\frac{\pi}{3}$ So $y=\tan ^2\left(\frac{\pi}{3}\right)$ $y=(\sqrt{3})^2=3$ |
