The value of tan ^2≤ft(sec ^-1 2) is :

The correct answer is option 2: 3

$y=\tan ^2\left(\sec ^{-1} 2\right)$

we know that $\sec ^{-1} 2=\cos ^{-1} \frac{1}{2}=\frac{\pi}{3}$

So $y=\tan ^2\left(\frac{\pi}{3}\right)$

$y=(\sqrt{3})^2=3$