If f be a function defined as $f(x)=\left[|x|\left[\frac{1}{|x|}\right]\right]$ when $|x|≠\frac{1}{n}$ and f(x) = 0 when $|x|=\frac{1}{n},n∈N$ [x] denotes the integral point of x, then when $|x|≠\frac{1}{n}$, f(x) is

0

$|x|≠\frac{1}{n}⇒\frac{1}{|x|}≠n⇒\frac{1}{|x|}=n+F$ where 0 < F < 1

$∴|x|\left[\frac{1}{|x|}\right]=\frac{1}{n+F}.n=\frac{n}{n+F}<1⇒f(x)=\left[|x|\left[\frac{1}{|x|}\right]\right]=0$