If angle  subtended by a chord on the major arc of a circle is 55 degree, then what will be the angle subtended by the same chord on the centre of the circle ?

110 degree

⇒ Let O, C and AB be the centre, a point on the major arc, and the aforementioned chord respectively.

So, the major arc for the AB chord is ACB.

Hence, \(\angle\)ACB = \({55}^\circ\)

Here, \(\angle\)AOB is the angle subtended by the same chord, AB on the centre of the circle.

According to the concept,

\(\angle\)AOB = 2 x \(\angle\)ACB

⇒ \(\angle\)AOB = 2 x \({55}^\circ\)

⇒ \(\angle\)AOB = \({110}^\circ\)

Therefore, the angle subtended by the same chord on the centre of the circle is \({110}^\circ\).