Practicing Success

Target Exam

CUET

Subject

-- Mathematics - Section A

Chapter

Continuity and Differentiability

Question:

$y=2^{-\log _2\left(x^3-5\right)}$, then $\frac{d y}{d x}$ is

Options:

$\frac{-3 x^2}{\left(x^3-5\right)^2}$

$\frac{x^2}{\left(x^3-5\right)^2}$

$\frac{3 x^2}{\left(x^3-5\right)^2}$

none of these

Correct Answer:

$\frac{-3 x^2}{\left(x^3-5\right)^2}$

Explanation:

$y=2^{\log _2\left(1 /\left(x^3-5\right)\right)}=\frac{1}{x^3-5}=\left(x^3-5\right)^{-1}$

$\frac{d y}{d x}=-1\left(x^3-5\right)^{-2} \times 3 x^2=\frac{-3 x^2}{\left(x^3-5\right)^2}$

Hence (1) is correct answer.