If the probability distribution of a ran

CUET Preparation Today

Start Free Mocks

Home Questions C3UTNJSWRY

Target Exam

CUET

Subject

-- Mathematics - Section B1

Chapter

Probability

Question:

If the probability distribution of a random variable X is as given below:

X=x:	-2	-1	0	1	2	3
P(X+x):	$\frac{1}{10}$	k	$\frac{1}{5}$	2k	$\frac{3}{10}$	k

The the value of k, is

Options:

$\frac{1}{10}$

$\frac{2}{10}$

$\frac{3}{10}$

$\frac{7}{10}$

Correct Answer:

$\frac{1}{10}$

Explanation:

The given distribution is a probability distribution.

$∴ P(X=-2)+P(X=-1)+P(X=0)+P(X=1)+P(X=2)+P(X+3)=1$

$⇒ \frac{1}{10}+k+\frac{1}{5}+2k +\frac{3}{10}+ k = 1⇒4k =\frac{4}{10}⇒ k = \frac{1}{10}$