CUET Preparation Today
| Find the value of $\int_{0}^{\pi/2}\log(\frac{4+3\sin x}{4+3\cos x})dx$ |
0 1 $\pi$ $\pi/2$ |
| 0 |
| Using ,$\int_{0}^{a}f(x)dx$=$\int_{0}^{a}f(a-x)dx$ we get $I=\int_{0}^{\pi/2}\log(\frac{4+3\cos x}{4+3\sin x})$. Hence $I=-I$. So $I=0$ |
