Find the value of $\int_{0}^{\pi/2}\log(\frac{4+3\sin x}{4+3\cos x})dx$
Answer & explanation
Correct answer: option 1
Using ,$\int_{0}^{a}f(x)dx$=$\int_{0}^{a}f(a-x)dx$ we get $I=\int_{0}^{\pi/2}\log(\frac{4+3\cos x}{4+3\sin x})$. Hence $I=-I$. So $I=0$