Target Exam

CUET

Subject

-- Applied Mathematics - Section B2

Chapter

Numbers, Quantification and Numerical Applications

Question:

Two pipes A and B can fill a cistern in 15 minutes and 30 minutes respectively. Both pipes are opened together, but after 5 minute pipe B is turned off. The cistern will be full in total:

Options:

10 minutes

7.5 minutes

15 minutes

12.5 minutes

Correct Answer:

12.5 minutes

Explanation:

The correct answer is Option (4) - 12.5 minutes

$\text{Rate of A} = \frac{1}{15},\;\; \text{Rate of B} = \frac{1}{30}$

$\text{Together rate} = \frac{1}{15} + \frac{1}{30} = \frac{1}{10}$

$\text{Work done in 5 minutes} = 5 \times \frac{1}{10} = \frac{1}{2}$

$\text{Remaining work} = 1 - \frac{1}{2} = \frac{1}{2}$

$\text{Now only A works}$

$\text{Time} = \frac{\frac{1}{2}}{\frac{1}{15}} = \frac{1}{2} \times 15 = 7.5 \text{ minutes}$

$\text{Total time} = 5 + 7.5 = 12.5 \text{ minutes}$

The cistern will be full in $12.5$ minutes.