When a current of 5 A flows through an ammeter, it gives full deflection. The resistance of ammeter is 20 Ω. If the same ammeter is to be used for measuring a maximum current of 10 A, then the ammeter must be connected to a resistance of : |
40 Ω in series 40 Ω in parallel 20 Ω in series 20 Ω in parallel |
20 Ω in parallel |
The correct answer is Option (4) → 20 Ω in parallel Given, full deflection current, $I_{full}=5A$ Resistance of the ammeter, $R=20Ω$ Maximum current to be measured, $I_{max}=10A$ $V_{ammeter}=I_{full}×R_{ammeter}$ [By Ohm's law] $V_{ammeter}=5×20=100V$ Let the Shunt resistor be $R_{shunt}$. The voltage across the shunt resistor must also be 100V when 5A flows through. $V_{shunt}=R_{shunt}×I_{shunt}$ $⇒R_{shunt}=\frac{100}{5}=20Ω$ Thus, the shunt resistor must be connected in parallel with the ammeter $20Ω$. |