If a straight wire of length 175cm and mass 250 gm is suspended freely in a uniform horizontal magnetic field of 0.7 T, then the current flowing through the wire is
Answer & explanation
Correct answer: option 3
$\text{For Equilibrium condition Net force is zero}$
$\Rightarrow ILB = mg $
$\Rightarrow I = \frac{mg}{LB} = \frac{0.25\times 9.8}{1.75\times 0.7} = 2A$