If a straight wire of length 175cm and mass 250 gm is suspended freely in a uniform horizontal magnetic field of 0.7 T, then the current flowing through the wire is

20 A 0.02 A 2A 0.2A

2A

$\text{For Equilibrium condition Net force is zero}$ $\Rightarrow ILB = mg $ $\Rightarrow I = \frac{mg}{LB} = \frac{0.25\times 9.8}{1.75\times 0.7} = 2A$