The instantaneous power supplied to a capacitor is given by
$P_c=i_m \cos(wt)v_m, \sin(wt)$
The average power over a complete cycle would be
Answer & explanation
Correct answer: option 3
The correct answer is Option (3) → Zero
The average power over a complete cycle is the time average of $P_c$. Since, $\sin(2ωt)$ is a sinusoidal function with a mean value of zero over one cycle.
$<P_c>=\frac{i_mv_m}{2}$ average $\sin(2ωt)$ = 0