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The instantaneous power supplied to a capacitor is given by $P_c=i_m \cos(wt)v_m, \sin(wt)$ The average power over a complete cycle would be |
$\frac{\cos^2 wt}{2}$ $\frac{\sin^2 wt}{2}$ Zero -1 |
Zero |
The correct answer is Option (3) → Zero The average power over a complete cycle is the time average of $P_c$. Since, $\sin(2ωt)$ is a sinusoidal function with a mean value of zero over one cycle. $<P_c>=\frac{i_mv_m}{2}$ average $\sin(2ωt)$ = 0 |
