Calculate the HCF of $\frac{12}{5},\frac{14}{15}$ and $\frac{16}{17}$.
Answer & explanation
Correct answer: option 3
HCF of fraction = \(\frac{HCF\;of\;numerator}{LCM\; of\;denominator}\)
The given fractions are : $\frac{12}{5},\frac{14}{15}$ and $\frac{16}{17}$.
LCM of 5, 15, 17 = 255
HCF of 12, 14, 16 = 2
The HCF of $\frac{12}{5},\frac{14}{15}$ and $\frac{16}{17}$. is = \(\frac{2}{255}\)