Calculate the HCF of $\frac{12}{5},\frac{14}{15}$ and $\frac{16}{17}$.

$\frac{4}{255}$ $\frac{3}{255}$ $\frac{2}{255}$ $\frac{1}{255}$

$\frac{2}{255}$

HCF of fraction = \(\frac{HCF\;of\;numerator}{LCM\; of\;denominator}\) The given fractions are :  $\frac{12}{5},\frac{14}{15}$ and $\frac{16}{17}$. LCM of 5, 15, 17 = 255 HCF of 12, 14, 16 = 2 The HCF of $\frac{12}{5},\frac{14}{15}$ and $\frac{16}{17}$. is = \(\frac{2}{255}\)