Practicing Success

Target Exam

CUET

Subject

Physics

Chapter

Wave Optics

Question:

In a young's double slit experiment, two slits are illuminated by a mixture of two wavelengths 1200nm and 1000nm . At 6.0 mm from the common central bright fringe on a screen 2 m away from the slits, a bright fringe of one interference pattern coincides with the bright fringe of other. Distance between the slits should be      

Options:

1.0 mm                          

1.5 mm  

 2.0 mm    

2.5 mm

Correct Answer:

 2.0 mm    

Explanation:

$ x = n\lambda \frac{D}{d} = (n+1)\lambda'\frac{D}{d}$

$1200 n= 1000 (n+1)$

$6n = 5n + 5  \Rightarrow n = 5$

$ x = 5\lambda \frac{D}{d} $

$ d = 5\lambda \frac{D}{x} = 5 \times 1200\times 10^{-9} \frac{2}{6\times 10^{-3}} = 2.0 mm$