Practicing Success
The points on the curve $2x=y^2$ which are nearest to the point (5, 0) lie in A. I Quadrant B. II Qudrant C. III Quadrant D. IV Quadrant Choose the correct answer from the options given below : |
A, B only B, C only C, D only A, D only |
A, D only |
The correct answer is Option (3) → A, D only Let point on curve be (x, y) needs to be minimum from curve $y^2=2x$ so $d=(x-5)^2+y^2$ $d=(x-5)^2+2x$ $d'=2(x-5)+2=0$ so $x=4$ so $y^2=2×4=8$ $y=±2\sqrt{2}$ Points $(4, ±2\sqrt{2})$ lie in Ist and IVth quadrant (A, D) |