Standard reduction electrode potential of four metals A, B, C and D are as follows. The correct order of increasing strength of reducing power is:
A. Metal A = +0.5 V
B. Metal B = -3.0 V
C. Metal C = -1.2 V
D. Metal D = -2.3 V
Choose the correct answer from the options given below:
Answer & explanation
Correct answer: option 1
The correct answer is option (1) → B > D > C > A
- Lower (more negative) Reduction Potential: The metal has a greater tendency to lose electrons (undergo oxidation), making it a stronger reducing agent.
- Higher (more positive) Reduction Potential: The metal has a greater tendency to gain electrons, making it a weaker reducing agent.
Therefore, the reducing power is inversely proportional to the standard reduction potential.
Step-by-Step Analysis
Based on the values given:
- Metal B: $-3.0\ V$ (Lowest $E^\circ \rightarrow$ Strongest reducing agent)
- Metal D: $-2.3\ V$
- Metal C: $-1.2\ V$
- Metal A: $+0.5\ V$ (Highest $E^\circ \rightarrow$ Weakest reducing agent)
Determining the Order
The question asks for the increasing strength of reducing power (from weakest to strongest):
$A < C < D < B$
However, the options provided use the greater than ($>$) symbol to show the hierarchy from strongest to weakest. Arranging them from the highest reducing power to the lowest:
B > D > C > A
Conclusion
The correct answer is Option 1: B > D > C > A.