Practicing Success
If 8a3 + 27b3 = 16 and 2a + 3b= 4, then find the value of 16a4 + 81b4. |
26 30 28 32 |
32 |
8a3 + b3 = 16 and 2a+ b = 4 we know - a3 + b3 = (a + b)(a2 - ab + b2) (a + b)2 = (a2 + 2ab + b2) = (8a3 + b3) = (2a + b)(4a2 - 2ab + b2) = 16 = 4 × (4a2 - 2ab + b2) ⇒ 4a2 - 2ab + b2 = 4 ⇒ (2a + b)2 = 4a2 + 4ab + b2 ⇒ 16 = 4a2 + 4ab + b2 Solving, = 6ab = 12 = ab = 2 Then, = 4a2 + b2 = 8 Then, 16a4 + b4 = (4a2 + b2)2 - 8a2b2 82 - 8 × (2)2 = 32 16a4 + b4 = 32 |