If $x = 3 + 2\sqrt{2}$, x > 0, then the value of $\sqrt{x}-\frac{1}{\sqrt{x}}$ is:
Answer & explanation
Correct answer: option 3
If $x = 3 + 2\sqrt{2}$
then \(\sqrt {x}\) = \(\sqrt {2}\) + 1
$\frac{1}{\sqrt{x}}$ = \(\sqrt {2}\) - 1
$\sqrt{x}-\frac{1}{\sqrt{x}}$ = \(\sqrt {2}\) + 1 - \(\sqrt {2}\) + 1 = 2