Practicing Success
Practicing Success
CUET Preparation Today
If $x = 3 + 2\sqrt{2}$, x > 0, then the value of $\sqrt{x}-\frac{1}{\sqrt{x}}$ is: |
1 $\sqrt{2}$ 2 $2\sqrt{2}$ |
2 |
If $x = 3 + 2\sqrt{2}$ then \(\sqrt {x}\) = \(\sqrt {2}\) + 1 $\frac{1}{\sqrt{x}}$ = \(\sqrt {2}\) - 1 $\sqrt{x}-\frac{1}{\sqrt{x}}$ = \(\sqrt {2}\) + 1 - \(\sqrt {2}\) + 1 = 2 |
