CUET Preparation Today
Find the integral: $\int (\sin x + \cos x) \, dx$ |
$\cos x - \sin x + C$ $\sin x-\cos x + C$ $-\cos x - \sin x + C$ $\cos 2x+C$ |
$\sin x-\cos x + C$ |
The correct answer is Option (2) → $\sin x-\cos x + C$ We have $\int (\sin x + \cos x) \, dx = \int \sin x \, dx + \int \cos x \, dx \text{}$ $= -\cos x + \sin x + C \text{}$ |
