Practicing Success
Practicing Success
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A rod of weight W is supported by two parallel knife edges A and B and is in equilibrium in a horizontal position. The knives are at a distance d from each other. The centre of mass of the rod is at distance x from A. The normal reaction on A is :- |
Wd/x [W(d-x)]/x [W(d-x)]/d Wx/d |
[W(d-x)]/d |
NAd = W(d - x) ⇒ NA = [W(d-x)]/d |
