Practicing Success
Practicing Success
CUET Preparation Today
If $sin^{-1}x+sin^{-1}y=\frac{2\pi}{3}, $ then the value of $cos^{-1}x+cos^{-1}y$ is : |
$\frac{2\pi}{3}$ $-\frac{\pi}{3}$ $\frac{\pi}{3}$ $-\frac{2\pi}{3}$ |
$\frac{\pi}{3}$ |
The correct answer is Option (3) → $\frac{\pi}{3}$ $\cos^{-1}x+\cos^{-1}y=\frac{π}{2}-\sin^{-1}x+\frac{π}{2}-\sin^{-1}y$ $=π-(\sin^{-1}x+\sin^{-1}y)$ $=π-\frac{2π}{3}=\frac{π}{3}$ |
