Practicing Success
The sum of two positive numbers is 240 and their HCF is 15. Find the number of pairs of numbers satisfying the given condition. |
3 2 4 1 |
4 |
Sum of other factors = \(\frac{Sum\;of\;Positive\;numbers}{HCF}\) = \(\frac{240}{15}\) = 16 Possibilities: - 1, 15 3, 13 5, 11 7, 9 ∴ 4 pairs are possible |