If $\begin{vmatrix} 2 & 4\\5 & 1\end{vmatrix}=\begin{vmatrix}2x & 4\\6 & x\end{vmatrix}$ then, x is equal to :
Answer & explanation
Correct answer: option 3
The correct answer is Option (3) → $±\sqrt{3}$
$\begin{vmatrix} 2 & 4\\5 & 1\end{vmatrix}=\begin{vmatrix}2x & 4\\6 & x\end{vmatrix}$
so $2-20=2x^2-24$
$2x^2=24-20+2$
$2x^2=6$
$x^2=3⇒x=±\sqrt{3}$