Practicing Success

Target Exam

CUET

Subject

Physics

Chapter

Electrostatic Potential and Capacitance

Question:

When a dielectric is inserted into an isolated and charged capacitor, the stored energy decreases to 33% of its original value. What is the value of dielectric constant?

Options:

2

1/2

3

1/3

Correct Answer:

1/3

Explanation:

U = \(\frac{C V^{2}}{2}\)

$U' = \frac{C' V^2}{2}$

U' = \(\frac{33}{100}\) \(\frac{C V^{2}}{2}\) 

$\frac{C' V^2}{2} =  \frac{33}{100} \frac{C V^{2}}{2}$

C' = k C

k C =\(\frac{33}{100}\) C

k = 0.33