Practicing Success
Practicing Success
CUET Preparation Today
In a triangle ABC, let $∠C=\frac{π}{2}$. If r is the inradius and R is the circumradius of the triangle, then 2(r + R) is equal to: |
a + b b + c c + a a + b + c |
a + b |
$\frac{c}{\sin C}=2R⇒c=2R$ [as C = 90°] Also $r=(s-c)\tan\frac{C}{2}=(s-c)$ [∵ tan 45° = 1] ⇒ 2r = 2s - 2c ⇒ 2r = a + b + c - 2c ⇒ 2r = a + b - c = a + b - 2R ⇒ 2(r + R) = a + b |
