If in a triangle PQR, sin P, sin Q, sin R are in A.P, then :
Answer & explanation
Correct answer: option 2
Altitudes PD, QE, RF are q sin R, r sin P, p sin Q, respectively
Where p, q, r are sides of the triangle
Apply sine rule : $\frac{q}{\sin Q}=\frac{r}{\sin R}=\frac{p}{\sin P}=K$
Attitudes are
⇒ K sin Q sin R, K sin R sin P, K sin P sin Q
$⇒\frac{K\sin P\sin Q\sin R}{\sin P}, \frac{K\sin P\sin Q\sin R}{\sin Q}, \frac{K\sin P\sin Q\sin R}{\sin R}$
Given, sin P, sin Q, sin R are in A.P.
⇒ Altitudes are in H.P.