Practicing Success
If a + b + c = 0, then find the value of $\frac{a^2+b^2+c^2}{a^2-bc}$. |
-1 1 2 -2 |
2 |
If a + b + c = 0 then find the value of $\frac{a^2+b^2+c^2}{a^2-bc}$ Put the value of a = 1 , b = -1 and c = 0 These values will satisfy the given conditions. $\frac{a^2+b^2+c^2}{a^2-bc}$ = $\frac{1^2+(-1)^2+0^2}{1^2-(-1)(0)}$ = $\frac{2}{1}$ = 2 |