If a + b + c = 0, then find the value of (a^2+b^2+c^2)/(a^2-bc).

If a + b + c = 0

then find the value of $\frac{a^2+b^2+c^2}{a^2-bc}$

Put the value of a = 1 , b = -1 and c = 0 These values will satisfy the given conditions.

$\frac{a^2+b^2+c^2}{a^2-bc}$ = $\frac{1^2+(-1)^2+0^2}{1^2-(-1)(0)}$

= $\frac{2}{1}$ = 2