A and B toss a fair coin each simultaneously 50 times. The probability that both of them will not get tail at the same toss is:

$(\frac{3}{4})^{50}$ $(\frac{2}{7})^{50}$ $(\frac{1}{8})^{50}$ $(\frac{7}{8})^{50}$

$(\frac{3}{4})^{50}$

On each toss of A and B, possible outcomes = {HH, TH, HT, TT} Favorable outcomes = {HH, TH, HT} P(TT not together) = $\frac{3}{4}.\frac{3}{4}.\frac{3}{4}.......50\,times=(\frac{3}{4})^{50}$