A and B toss a fair coin each simultaneously 50 times. The probability that both of them will not get tail at the same toss is:
Answer & explanation
Correct answer: option 1
On each toss of A and B, possible outcomes = {HH, TH, HT, TT}
Favorable outcomes = {HH, TH, HT}
P(TT not together) = $\frac{3}{4}.\frac{3}{4}.\frac{3}{4}.......50\,times=(\frac{3}{4})^{50}$