A fair coin is tossed k times. If the probability of getting exactly six tails is equal to the probability of getting exactly 8 tails, then the probability of getting exactly 3 tails is:

$\frac{2}{15}$ $\frac{37}{2^{12}}$ $\frac{1}{2^{14}}$ $\frac{91}{2^{12}}$

$\frac{37}{2^{12}}$

The correct answer is Option (2) → $\frac{37}{2^{12}}$