The total surface area of a right pyramid, with base as a square of side 8 cm. is 208 cm2. What is the slant height (in cm) of the pyramid?
Answer & explanation
Correct answer: option 3
We know that,
Lateral surface area = \(\frac{1}{2}\) × Perimeter of base × slant height
Total surface area = Lateral surface area + Area of the base
Now,
208 = Lateral surface area + 82
= 208 - 64 = Lateral surface area
Lateral surface area = 144
Again,
144 = \(\frac{1}{2}\) × 4 × 8 × slant height
slant height = \(\frac{144}{16}\) = 9 cm