The total surface area of a right pyramid, with base as a square of side 8 cm. is 208 cm². What is the slant height (in cm) of the pyramid?

9

We know that,

Lateral surface area = \(\frac{1}{2}\) × Perimeter of base × slant height

Total surface area = Lateral surface area + Area of the base

Now,

208 = Lateral surface area + 8²

= 208 - 64 = Lateral surface area

Lateral surface area = 144

Again,

144 = \(\frac{1}{2}\) × 4 × 8 × slant height

slant height = \(\frac{144}{16}\) = 9 cm