Practicing Success

Target Exam

CUET

Subject

Chemistry

Chapter

Inorganic: D and F Block Elements

Question:

The transition elements exhibit variable oxidation states because (n −1)d electrons can also participate in bonding as the energy difference between (n −1)d and ns orbitals is very small. The oxidation states of transition elements change in units of one whereas in p-block elements oxidation states normally differ by two units. The minimum oxidation state exhibited by a transition element is equal to the number of electrons in the ns orbital. The maximum oxidation state that can be exhibited by a transition element is equal to the total number of electrons present in both ns and (n −1)d orbitals. The elements in the middle exhibit more oxidation states, e.g., manganese exhibits from +2 to +7. The elements at the extreme ends exhibit a lesser number of oxidation states. This is because of the availability of lesser electrons to lose or to share in the earlier elements or too many d electrons due to which lesser number of unpaired electrons to share at the end. Due to anomalous electronic configuration, chromium and copper can exhibit a minimum oxidation state of +1. In the first series, the maximum oxidation state increases up to Mn and then decreases from Fe onwards. In the first series, Mn exhibits the maximum oxidation state +7. In the second series, a stable maximum oxidation state is exhibited by technetium, and an unstable maximum oxidation state +8 is exhibited by ruthenium. In the third series, stable maximum oxidation +8 is exhibited by osmium. The transition metal ions having completely filled and exactly half-filled d-sub level and those having octet in their outermost shell are stable. The stabilities of Cr3+ and Mn4+ ions is due to high lattice energy in solid state and high hydration energy in their aqueous solutions. Fe3+ ion is more stable than Fe2+ ion because of the stable half-filled 3d5 electronic configuration in Fe3+. In the last five elements of the 3d series, the 3d electrons are stabilized and require more energy for their removal because the 3d orbital contracts more and come nearer to the nucleus with an increase in nuclear charge. Thus in the last five elements, the +2 oxidation state becomes more stable (except Fe3+ ).

Maximum number of oxidation states of the transition elements is derived from the following configuration

Options:

ns electrons

( n −1)d electrons

( n +1)d electrons

ns and (n −1)d electrons

Correct Answer:

ns and (n −1)d electrons

Explanation:

The answer is (4) ns and (n-1)d electrons.

The maximum number of oxidation states of a transition element is derived from the number of electrons in its ns and (n-1)d orbitals. The (n-1)d orbitals are filled with electrons before the ns orbitals, so they are higher in energy. However, the (n-1)d orbitals are also smaller than the ns orbitals, so they are more tightly held by the nucleus. This means that the (n-1)d electrons are more easily lost than the ns electrons.

The number of oxidation states that a transition element can exhibit depends on the number of electrons in its (n-1)d and ns orbitals. For example, iron can have oxidation states of +2, +3, and +4 because it has 6 electrons in its (n-1)d orbitals and 2 electrons in its ns orbital.

Here is a table that summarizes the orbitals that contribute to the maximum oxidation states of transition elements:

Orbital

Description

ns electrons

The s orbital in the n shell.

(n-1)d electrons

The d orbitals in the n-1 shell.