If $g (f(x)) =|\sin x|$ and $f (g(x)) = (\sin \sqrt{x})^2$, then
Answer & explanation
Correct answer: option 1
We have,
$f(g(x))=(\sin\sqrt{x})^2$ and, $g(f(x))=|\sin x|=\sqrt{\sin^2x}$
$⇒g(x) = \sqrt{x}$ and $f(x) = (\sin x)^2$
If $g (f(x)) =|\sin x|$ and $f (g(x)) = (\sin \sqrt{x})^2$, then
Correct answer: option 1
We have,
$f(g(x))=(\sin\sqrt{x})^2$ and, $g(f(x))=|\sin x|=\sqrt{\sin^2x}$
$⇒g(x) = \sqrt{x}$ and $f(x) = (\sin x)^2$