What is the area of a triangle whose sides measure 5 cm, 6 cm and 7 cm?
Answer & explanation
Correct answer: option 4
We know that,
Area of a triangle = \(\sqrt {s(s-a)(s-b)(s-c) }\)
The three sides measure 5 cm, 6 cm and 7 cm
Semi perimeter = \(\frac{5 + 6 + 7}{2}\) = 9
Put them in the above formula,
Area of a triangle = \(\sqrt {9(9-5)(9-6)(9-7) }\)
= \(\sqrt {9(4)(3)(2) }\) = \(\sqrt {216}\) = 14.6969 cm2