Practicing Success
CUET Preparation Today
CUET
Physics
Atoms
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d
for electron in an orbit $\frac{mv^2}{r} = \frac{ke^2}{r^2}$
$\Rightarrow mv^2 = \frac{ke^2}{r}$
$\Rightarrow K.E = \frac{1}{2}mv^2 = \frac{ke^2}{2r}$