Practicing Success
If (a2 - 16) = \(\frac{-2}{a^2}\), then find \(\sqrt { \frac{156\;a^2\;×\;250}{13\;a^4\;+\;104\;a^2\;+\;26} }\) |
5\(\sqrt {7}\) 5\(\sqrt {5}\) 7\(\sqrt {5}\) 10\(\sqrt {5}\) |
5\(\sqrt {5}\) |
⇒ a2 - 16 = \(\frac{-2}{a^2}\) ⇒ a2 + \(\frac{2}{a^2}\) = 16 Now, ⇒ \(\sqrt { \frac{156\;a^2\;×\;250}{13\;a^4\;+\;104a^2\;+\;26}}\) ⇒ \(\sqrt { \frac{156\;a^2\;×\;250}{a^2\;(13\;a^2\;+\;104\;+\;\frac{26}{a^2})}}\) ⇒ \(\sqrt { \frac{156\;×\;250}{13\left(a^2\;+\;\frac{2}{a^2}\right)\;+\;104} }\) ⇒\(\sqrt { \frac{156\;×\;250}{13\;×\;16\;+\;104} }\) = \(\sqrt { \frac{39000}{312} }\) = \(\sqrt {125}\) = 5\(\sqrt {5}\) |