The depletion layer in a silicon diode is 1μm wide and its knee potential is 0.6V, then the electric field in the depletion layer will be:
Answer & explanation
Correct answer: option 3
$E=-\frac{dV}{dr}=\frac{0.6}{10^{-6}}=6 × 10^5 V/m$
The depletion layer in a silicon diode is 1μm wide and its knee potential is 0.6V, then the electric field in the depletion layer will be:
Correct answer: option 3
$E=-\frac{dV}{dr}=\frac{0.6}{10^{-6}}=6 × 10^5 V/m$