Practicing Success
Practicing Success
CUET Preparation Today
The depletion layer in a silicon diode is 1μm wide and its knee potential is 0.6V, then the electric field in the depletion layer will be: |
$0.6 V/m$ $6 × 10^4 V/m$ $6 × 10^5 V/m$ Zero |
$6 × 10^5 V/m$ |
$E=-\frac{dV}{dr}=\frac{0.6}{10^{-6}}=6 × 10^5 V/m$ |
