Practicing Success

Target Exam

CUET

Subject

Chemistry

Chapter

Physical: Solutions

Question:

Match List-I with List-II

List-I

List-II

(A) \(K_4[Fe(CN)_6]\)

(I) 3

(B) \(K_2SO_4\)

(II) 0.5

(C) \(CH_3COOH\) in Benzene

(III) 5

(D) \(KCl\)

(IV) 2

Choose the correct answer from the options given below:

Options:

A-III, B-I, C-II, D-IV

A-III, B-I, C-IV, D-II

A-II, B-I, C-III, D-IV

A-II, B-III, C-I, D-IV

Correct Answer:

A-III, B-I, C-II, D-IV

Explanation:

The correct answer is (1) A-III, B-I, C-II, D-IV.

(A) \(K_4[Fe(CN)_6]\) - This is a complex salt consisting of potassium ions (K⁺) and the complex ion \([Fe(CN)_6]^{4-}\). When it dissolves in water, it dissociates into five ions: 4 K⁺ ions and 1 \([Fe(CN)_6]^{4-}\) ion. So, it produces a total of 5 ions.

(B) \(K_2SO_4\) - This is a simple salt made up of potassium ions (K⁺) and sulfate ions (\(SO_4^{2-}\)). When it dissolves in water, it dissociates into two ions: 2 K⁺ ions and 1 \(SO_4^{2-}\) ion. So, it produces a total of 2 ions.

(C) \(CH_3COOH\) in Benzene - This represents acetic acid (\(CH_3COOH\)) dissolved in benzene, a non-polar solvent. In non-polar solvents, acids typically do not dissociate as fully as they do in water (an aqueous solution). The degree of dissociation is indicated as 0.5, which means that only half of the acetic acid molecules would ionize to form \(CH_3COO^-\) ions and \(H^+\) ions, resulting in fewer ions.

(D) \(KCl\) - This is a simple salt composed of potassium ions (K⁺) and chloride ions (Cl⁻). When it dissolves in water, it dissociates into two ions: 1 K⁺ ion and 1 Cl⁻ ion. So, it produces a total of 2 ions.

Given these explanations, the correct matching is:
(A) \(K_4[Fe(CN)_6]\) - (III) 5
(B) \(K_2SO_4\) - (I) 3
(C) \(CH_3COOH\) in Benzene - (II) 0.5 (note that this appears to be incorrect based on the explanation)
(D) \(KCl\) - (IV) 2