The three medians AX, BY and CZ of ΔABC intersect at point L. If the area of ΔABC is 42 cm2, then the area of the quadrilateral BXLZ is?
Answer & explanation
Correct answer: option 2
Medians cut the area of triangle in six equal parts.
ΔBLX = \(\frac{1}{6}\) ΔABC = \(\frac{1}{6}\) × 42 cm2 = 7 cm2
Quadrilateral BXLZ = 7 cm2 + 7 cm2 = 14 cm2