The three medians AX, BY and CZ of ΔABC intersect at point L. If the area of ΔABC is 42 cm2, then the area of the quadrilateral BXLZ is? |
7 cm2 14 cm2 6 cm2 12 cm2 |
14 cm2 |
Medians cut the area of triangle in six equal parts. ΔBLX = \(\frac{1}{6}\) ΔABC = \(\frac{1}{6}\) × 42 cm2 = 7 cm2 Quadrilateral BXLZ = 7 cm2 + 7 cm2 = 14 cm2 |